In an equilibrium `A+B hArr C+D`, A and B are mixed in vessel at temperature T. The initial concentration of A was twice the initial concentration of B. After the equilibrium has reaches, concentration of C was thrice the equilibrium concentration of B. Calculate `K_(c)`.

Options

A. 4.5
B. 9
C. 1.8
D. 0.9

Answer

C

Explanation

Let the concentration of A be 2 B be 1.
`A+B Leftrightarrow C+D`
`{:(,"Initial",2,1,0,0),(,"At equilibriumn",(2-x),(1-x),x,x):}`
Given that, `x=3(1-x), rArr x=3/4`
`K_(c)=((3/4) (3/4))/((2-3//4) (1-3//4))=9/5=1.8`