The value of `K_(c)` for the reaction `2A hArr B+C` is `2.0xx10^(-3)`. At a given time, the composition of reaction mixture is `[A]=[B]=[C]=3xx10^(-4)M`. In which direction the reaction will proceed?

Options

A. Forward
B. Backward
C. At equilibrium
D. Forward or Backward

Answer

B

Explanation

For the reaction the reaction quotient `Q_(c)` is given by, `Q_(c)=[B] [C]//[A]^(2)`,
as `[A]=[B]=[C]=3 xx 10^(-4) M`
`Q_(C)=(3 xx 10^(-4)) (3 xx 10^(-4))// (3xx 10^(-4))^(2)=1`
as `Q_(c) gt K_(c)` so the reaction will proceed in the reverse direction.