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2 "mole" of PCl(5) were heated in a clos...

`2 "mole"` of `PCl_(5)` were heated in a closed vessel of `2 litre` capacity. At equilibrium `40%` of `PCl_(5)` dissociated into `PCl_(3)` and `Cl_(2)`. The value of the equilibrium constant is:

A

0.25 lit/mole

B

1.31 lit/mole

C

0.76 lit/mole

D

2.6 lit/mole

Text Solution

Verified by Experts

The correct Answer is:
C

`PCl_(3)+Cl_(2) Leftrightarrow PCl_(5)`
`"Initial",1,2,0`
Reacted & formed at equilibrium `1-x " "2-xx(x=0.3)`
`K_(c)=[(0.3)/(3)] xx [3/(1.7)] xx (3)/(0.7)`
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NARAYNA-CHEMICAL EQUILIBRIUM-Exercise -II (H.W.)
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