When `20 g` of `CaCO_(3)` were put into `10 litre` flask and heated to `800^(@)C`, `35%` of `CaCO_(3)` remained unreacted at equilibrium. `K_(p)` for decomposition of `CaCO_(3)` is :

Options

A. 25g, 14g, 1/22.4 mol/lit
B. 1,1 1/89.6 mol/lit
C. 25, 14, 1/89.6 mol/lit
D. 1, 1, 1

Answer

B

Explanation

For solid active mass is taken as unity
`underset((S))(CaCO_(3)) Leftrightarrow underset((S))(CaO)+underset((g))(CO_(2))`
`{:(,"given ",50gms,22gms),(,50% diss,25g,11g):}`
Active mass of `CO_(2)=((11//44))/(22.4)=(1)/(89.6)"mol/lit."`