If the concentration of `OH^(-)` ions in the reaction
`Fe(OH)_(3)(s)hArrFe^(3+)(aq.)+3OH^(-)(aq.)`
is decreased by `1//4` times, then the equilibrium concentration of `Fe^(3+)` will increase by

Options

A. 4 times
B. 8 times
C. 16 times
D. 64 times

Answer

D

Explanation

`K=[Fe^(3+)] [OH^(-)]^(3)`
New `K.=[xFe^(3)-] [1/4 OH^(-)]^(3)`
`=x[Fe^(3+) xx 1/64 [OH^(-)]^(3)`
For `K=K," "x=64`