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The reaction of dimerisation of NO(2) in...

The reaction of dimerisation of `NO_(2)` in `N_(2)O_(4)` is `2NO_(2)hArrN_(2)O_(4)`. The reaction is carried out by taking `1` mole each of `NO_(2)` and `N_(2)O_(4)` in a closed vessel of `1` litre at `400 K`. The equilibrium pressure was found to be `77 atm`.
The ratio of partial pressures of `NO_(2)` and `N_(2)O_(4)` at equilibrium is:

A

0.16 bar

B

0.32 bar

C

0.48 bar

D

0.64 bar

Text Solution

Verified by Experts

The correct Answer is:
D
`N_(2)O_(4) Leftrightarrow 2NO_(2)`
Initial mol. 0.1
Eq. mol 0.1-x 2x
Total no. of moles at equilibrium =(0.1+x)
PV =nRT
6x 1=(0,1+x) (0.083) (400)
x=0.08
`P_(N_(2)O_(4))=((0.1-0.08))/(0.18) xx 6, 0.64 bar`
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