Home
Class 11
CHEMISTRY
In the dissociation of N(2)O(4) into NO(...

In the dissociation of `N_(2)O_(4)` into `NO_(2), (1+ alpha)` values with the vapour densities ratio `((D)/(d))` is given by: [`alpha` degree of dissociation, D-vapour density before dissociation, d-vapour density after dissociation]

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(2)O_(4) Leftrightarrow 2NO_(2)`
n=2
`alpha =(D-d)/(d(n-1)), x=(D-d)/(d(2-1)), x=(D-d)/(d), x=D/d, -1 rArr 1+x=D/d`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    NARAYNA|Exercise Exercise -3|24 Videos

  • CHEMICAL EQUILIBRIUM

    NARAYNA|Exercise Exercise -IV|33 Videos

  • CHEMICAL EQUILIBRIUM

    NARAYNA|Exercise Exercise -II (C.W.)|51 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    NARAYNA|Exercise EXERCISE -4|54 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY

    NARAYNA|Exercise EXERCISE - 4|17 Videos

Similar Questions

Explore conceptually related problems

In the dissociation of N_(2)O_(4) into NO_(2). (1+x) values with the vapour densities ratio ((D)/(d)) is given by :

Vapour density and degree of dissociation| Suppression

During thermal dissociation of a gas, the vapour density.

Question based on Vapour density and degree of dissociation | Suppression

The equation alpha=(D-d)/((n-1)d) is correctly matched for: ( alpha is the degree of dissociation, D and d are the vapour densities before and after dissociation, respectively).

The vapour density of fully dissociated NH_(4)Cl would be

Degree OF Dissociation (α) || Mavg and Vapour Density in Terms OF α

NARAYNA-CHEMICAL EQUILIBRIUM-Exercise -II (H.W.)
  1. The equilibrium constant for the given reaction: SO(3(g))hArrSO(2(g)...

    Text Solution

    |

  2. K(c) for 3//2H(2)+1//2N(2) hArr NH(3) are 0.0266 and 0.0129 atm^(-1), ...

    Text Solution

    |

  3. For the following reactions (1) , (2) and (3) equilibrium constants ar...

    Text Solution

    |

  4. For the reaction 2NO(2)(g) hArr 2NO(g)+O(2)(g) K(c)=1.8xx10^(-6) at ...

    Text Solution

    |

  5. The vapour pressure of water at 25°C is 0.0313 atm. Calculate the valu...

    Text Solution

    |

  6. One dm^(3) of hydrogen is present in a flask at a pressure of 10^(-12)...

    Text Solution

    |

  7. For the reaction at 25^(@)C, C(2)H4(g)+H(2)(g) LeftrightarrowC(2)H(6...

    Text Solution

    |

  8. In the dissociation of N(2)O(4) into NO(2), (1+ alpha) values with the...

    Text Solution

    |

  9. The degree of dissociation of PCl(5) will be more at ………. pressure.

    Text Solution

    |

  10. Before equilibrium is set-up for the chemical reaction, N(2)O(4)hArr 2...

    Text Solution

    |

  11. For reacrtion 2NOC1(g) hArr 2NO(g) + C1(2)(g) , K(c) at 427^(@)C is 3x...

    Text Solution

    |

  12. N(2)O(4) is dissociated to 33% and 50% at total pressure P(1) and P(2)...

    Text Solution

    |

  13. The following equilibrium constants are given : N(2) + 3 H(3) hArr ...

    Text Solution

    |

  14. For the reaction, PCl(3) (g)+Cl(2) (g) Leftrightarrow PCl(5) (g)" at "...

    Text Solution

    |

  15. The equilibrium constant K(p(1)) and K(p(2)) for the reactions XhArr2Y...

    Text Solution

    |

  16. Rate of diffucion of ozonized oxygen is 0.4sqrt5 times that of pure ox...

    Text Solution

    |

  17. For the reaction, SO(2)(g) + (1)/(2)O(2)(g)hArrSO(3) (g), If K(p) = K(...

    Text Solution

    |

  18. For the reaction, N(2)O(4)(g)hArr 2NO(2)(g) the reaction connectin...

    Text Solution

    |

  19. The prepation of SO(3)(g) by reaction SO(2)(g)+(1)/(2)O(2)(g)hArrSO(3)...

    Text Solution

    |

  20. For a reaction at equilibrium PCl(5(g)) Leftrightarrow pcL(3(G))+Cl(2(...

    Text Solution

    |