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N(2)O(4) is dissociated to 33% and 50% a...

`N_(2)O_(4)` is dissociated to `33%` and `50%` at total pressure `P_(1)` and `P_(2)atm` respectively. The ratio of `P_(1)//P_(2)` is:

A

`P_(1): P_(2)=7:4`

B

`P_(1): P_(2)=7:2`

C

`P_(1):P_(2)=4:7`

D

`P_(1):P_(2)=3:4`

Text Solution

Verified by Experts

The correct Answer is:
C

`N_(2)O_(4) Leftrightarrow 2NO_(2)`
Eq. mol `(x-alpha) " "2alpha`
`alpha=(75)/(100) x x=0.75 x, n=1.75 x, (P_(1))/(n_(1))=(P_(2))/n_(2)`
`P_(1)/x=P_(2)/(1.75x), P_(1)/P_(2)=(1)/(1.75)`
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