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the value of equilibrium constant for th...

the value of equilibrium constant for the reaction
`HI(g) hArr 1//2 H_(2) (g) +1//2 I_(2) (g) " is " 8.0`
The equilibrium constant for the reaction
`H_(2) (g) +I_(2) (g) hArr 2HI(g)` will be

A

`1/64`

B

16

C

`1/8`

D

`1/16`

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The correct Answer is:
A
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  16. For the reversible reaction, N(2)(g)+3H(2) (g) Leftrightarrow 2NH(3) ...

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