Give the product of the following
(i) `C_6H_5CH=CH_2+HBr rarr`
`CH_3CH_2CH=CH_2+HCl rarr`
(iii) `C_6H_5CH_2CH=CH_2+HBroverset("Peroxide")rarr`

Explanation

To solve the question, we need to find the products of three different reactions involving alkenes and hydrogen halides. Let's go through each reaction step by step.

### Reaction (i):
**C₆H₅CH=CH₂ + HBr → ?**

1. **Identify the alkene and the reagent**: The alkene is styrene (C₆H₅CH=CH₂) and the reagent is hydrogen bromide (HBr).
2. **Apply Markovnikov's Rule**: According to Markovnikov's rule, when HBr adds to an alkene, the hydrogen atom will attach to the carbon with the greater number of hydrogen atoms.
- In this case, the double bond is between the second carbon (CH) and the third carbon (CH₂). The second carbon has one hydrogen atom, and the third carbon has two hydrogen atoms.
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