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Ethyl isocyanide on reduction with sodiu...

Ethyl isocyanide on reduction with sodium and alcohol gives:

A

Ethyl amine

B

Propyl amine

C

Dimethylamine

D

Ethyl methyl amine

Text Solution

Verified by Experts

The correct Answer is:
D
`CH_(3)-CH_(2)-N-=C+4H to CH_(3)-CH_(2)-NH-CH_(3)`
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