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If A={:[(2,3,-1),(5,6,1)]:}, then find ...

If `A={:[(2,3,-1),(5,6,1)]:}`, then find
(a) -A , (b)3A , (c ) `(1)/(4)A`.

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(a) `-A--{:[(2,3,-1),(5,6,1)]:}`
`={:[(-1xx2,-1xx3,-1xx(-1)),(-1xx5,-1xx6,-1xx1)]:}={:[(-2,-3,1),(-5,-6,-1)]:}`.
(b) `3A=3{:[(2,3,-1),(5,6,1)]:}`
`={:[(3xx2,3xx3,3(-1)),(3xx5,3xx6,3xx1)]:}={:[(6,9,-3),(15,18,3)]:}`
`(1)/(4)A=(1)/(4){:[(2,3,-1),(5,6,1)]:}`
`={:[((1)/(4)xx2,(1)/(4)xx3,(1)/(4)xx(-1)),((1)/(4)xx5,(1)/(4)xx6,(1)/(4)xx1)]:}={:[((1)/(2),(3)/(4),(-1)/(4)),((5)/(4),(3)/(2),(1)/(4))]:}`
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