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Find the cube roots of the following usi...

Find the cube roots of the following using prime factorisation method

A

5832

B

19683

C

9261

D

405224

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To find the cube roots of the given numbers using the prime factorization method, we will follow these steps: ### Step 1: Prime Factorization We will start by factorizing each number into its prime factors. 1. **For the number 5, 8, 3, 2:** - 5 is a prime number. - 8 = 2 × 2 × 2 = \(2^3\) - 3 is a prime number. - 2 is a prime number. - So, the prime factorization of 5, 8, 3, 2 is: \[ 5^1 \times 2^3 \times 3^1 \] 2. **For the number 19683:** - 19683 can be factorized by dividing by 3: - 19683 ÷ 3 = 6561 - 6561 ÷ 3 = 2187 - 2187 ÷ 3 = 729 - 729 ÷ 3 = 243 - 243 ÷ 3 = 81 - 81 ÷ 3 = 27 - 27 ÷ 3 = 9 - 9 ÷ 3 = 3 - 3 ÷ 3 = 1 - So, the prime factorization of 19683 is: \[ 3^9 \] 3. **For the number 9261:** - 9261 can be factorized by dividing by 3: - 9261 ÷ 3 = 3087 - 3087 ÷ 3 = 1029 - 1029 ÷ 3 = 343 - 343 = \(7^3\) - So, the prime factorization of 9261 is: \[ 3^3 \times 7^3 \] 4. **For the number 405224:** - 405224 can be factorized by dividing by 2: - 405224 ÷ 2 = 202612 - 202612 ÷ 2 = 101306 - 101306 ÷ 2 = 50653 (not divisible by 2 anymore) - Now, factor 50653 by dividing by 37: - 50653 ÷ 37 = 1371 - 1371 ÷ 37 = 37 - So, the prime factorization of 405224 is: \[ 2^3 \times 37^3 \] ### Step 2: Grouping the Factors Now we will group the prime factors in sets of three to find the cube roots. 1. **For 5, 8, 3, 2:** - The factors are \(5^1\), \(2^3\), and \(3^1\). - Grouping gives us: \[ \sqrt[3]{5^1 \times 2^3 \times 3^1} = 2 \times \sqrt[3]{5 \times 3} = 2 \times \sqrt[3]{15} \] 2. **For 19683:** - The factors are \(3^9\). - Grouping gives us: \[ \sqrt[3]{3^9} = 3^{9/3} = 3^3 = 27 \] 3. **For 9261:** - The factors are \(3^3\) and \(7^3\). - Grouping gives us: \[ \sqrt[3]{3^3 \times 7^3} = 3^{3/3} \times 7^{3/3} = 3 \times 7 = 21 \] 4. **For 405224:** - The factors are \(2^3\) and \(37^3\). - Grouping gives us: \[ \sqrt[3]{2^3 \times 37^3} = 2^{3/3} \times 37^{3/3} = 2 \times 37 = 74 \] ### Final Answers - The cube root of 5, 8, 3, 2 is \(2 \sqrt[3]{15}\). - The cube root of 19683 is \(27\). - The cube root of 9261 is \(21\). - The cube root of 405224 is \(74\).
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