Which is stronger reducing agent `Cr^(2+)` or `Fe^(2 +)`?

Explanation

`Cr^(2+)` and `Fe^(2 +)`
Cr (Z = 24) Electronic configuration-`[Ar] 3d^(5) 4s^(1)`
`Cr^(2+)` Electronic configuration-`[Ar] 3d^(4) 4s^(0)`
Fe (Z = 26) Electronic configuration-`[Ar] 3d^(6) 4s^(2)`
`Fe^(2+)` Electronic configuration-`[Ar] 3d^(6)4s^(0)`
If standard electrode potential (E) of a metal is large and negative, the metal is a powerful reducing agent.
`Cr^(2+)+ 2e^(-) to Cr E^(0) = -0.91V`
`Fe^(2+) + 2e^(-) to Fe E^(0) = -0.44 V`
By comparing the above equation, `Cr^(2+)` is a powerful reducing agent.