To complete a certain work, C working alone takes twice as long as A and B working together. A working alone takes 3 times as long as B and C working together. All the three together can complete the work in 5 days. How long would each take to complete th work individually?

Explanation

Given that, 3 times A's daily work =(B+C)'s 1 day's work.
Adding 1 time A's daily work to both sides, we get 4 times A's daily work.
`implies (A+B+C)'s` daily work=4 times A's daily work. But (A+B+C)'s daily work`=(1)/(5)`.
`:.` A's daily work=1/20, A takes 20 days to do the work . Also,given 2 times C's daily work=(A+B)'s daily work. Adding 1 time C's daily work to both sides, we get 3 times C's daily work =(A+B+C)'s daily work=1/5
`:.` C's daily work=1/15, C takes 15 days to do the work.
`:.` B's daily work`=(1)/(5)((1)/(20)+(1)/(15))=(1)/(12)`, B takes 12 days to do the work.
`:.` The work can be done by A alone in 20 days, B alone in days and C alone in 15 days.