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6 men and 9 women can do a piece of work...

6 men and 9 women can do a piece of work in 4 days.4 men and 3 women can do it in 8 days. In how many days can 20 men and 6 women do the same work ?

A

2

B

3

C

1

D

4

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The correct Answer is:
To solve the problem step by step, we will first determine the work done by men and women in terms of a common unit of work, and then use that to find out how many days 20 men and 6 women will take to complete the same work. ### Step 1: Determine the total work done by 6 men and 9 women in 4 days. Let the work done by 1 man in 1 day be \( M \) and the work done by 1 woman in 1 day be \( W \). From the first scenario: - 6 men and 9 women can complete the work in 4 days. - Total work done = \( (6M + 9W) \times 4 \) ### Step 2: Determine the total work done by 4 men and 3 women in 8 days. From the second scenario: - 4 men and 3 women can complete the work in 8 days. - Total work done = \( (4M + 3W) \times 8 \) ### Step 3: Set the two expressions for total work equal to each other. Since both scenarios complete the same work, we can set the equations equal: \[ (6M + 9W) \times 4 = (4M + 3W) \times 8 \] ### Step 4: Simplify the equation. Expanding both sides: \[ 24M + 36W = 32M + 24W \] ### Step 5: Rearranging the equation. Rearranging gives: \[ 24M - 32M = 24W - 36W \] \[ -8M = -12W \] Dividing both sides by -4: \[ 2M = 3W \] Thus, we can express \( M \) in terms of \( W \): \[ M = \frac{3}{2}W \] ### Step 6: Substitute \( M \) in terms of \( W \) into one of the work equations. We can substitute \( M \) into the first work equation: \[ (6 \times \frac{3}{2}W + 9W) \times 4 = Total Work \] Calculating: \[ (9W + 9W) \times 4 = 18W \times 4 = 72W \] So, the total work is \( 72W \). ### Step 7: Determine the work done by 20 men and 6 women in a day. Now, we need to find out how many days it will take for 20 men and 6 women to complete the same work. The work done by 20 men and 6 women in one day is: \[ (20M + 6W) = (20 \times \frac{3}{2}W + 6W) = (30W + 6W) = 36W \] ### Step 8: Calculate the number of days required. To find the number of days \( D \) required to complete the total work of \( 72W \): \[ D = \frac{Total Work}{Work \, done \, in \, one \, day} = \frac{72W}{36W} = 2 \, days \] ### Final Answer: Thus, 20 men and 6 women can complete the work in **2 days**. ---

To solve the problem step by step, we will first determine the work done by men and women in terms of a common unit of work, and then use that to find out how many days 20 men and 6 women will take to complete the same work. ### Step 1: Determine the total work done by 6 men and 9 women in 4 days. Let the work done by 1 man in 1 day be \( M \) and the work done by 1 woman in 1 day be \( W \). From the first scenario: - 6 men and 9 women can complete the work in 4 days. - Total work done = \( (6M + 9W) \times 4 \) ...
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