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P,Q and R can do a piece of work in 18 d...

P,Q and R can do a piece of work in 18 days, 36 days and 54 day respectively. They start the work together but Q and R leave 1 day and 5 days respectively, before the completion of work. In how many days has the work been completed ?

A

10

B

11

C

`10(7)/(11)`

D

`10(9)/(11)`

Text Solution

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The correct Answer is:
To solve the problem step by step, we will calculate the efficiency of each worker and then determine how long they worked together before Q and R left. ### Step 1: Calculate the efficiency of P, Q, and R - P can complete the work in 18 days, so his efficiency is: \[ \text{Efficiency of P} = \frac{1}{18} \text{ of the work per day} \] - Q can complete the work in 36 days, so his efficiency is: \[ \text{Efficiency of Q} = \frac{1}{36} \text{ of the work per day} \] - R can complete the work in 54 days, so his efficiency is: \[ \text{Efficiency of R} = \frac{1}{54} \text{ of the work per day} \] ### Step 2: Find a common total work unit To make calculations easier, we can assume the total work is 108 units (the least common multiple of 18, 36, and 54). ### Step 3: Calculate the daily work done by each worker - P's daily work: \[ \text{Work done by P in one day} = \frac{108}{18} = 6 \text{ units} \] - Q's daily work: \[ \text{Work done by Q in one day} = \frac{108}{36} = 3 \text{ units} \] - R's daily work: \[ \text{Work done by R in one day} = \frac{108}{54} = 2 \text{ units} \] ### Step 4: Set up the equation for total work done Let \( x \) be the total number of days they worked together. - P works for \( x \) days. - Q works for \( x - 1 \) days (leaves 1 day before completion). - R works for \( x - 5 \) days (leaves 5 days before completion). The total work done can be expressed as: \[ \text{Total Work} = \text{Work by P} + \text{Work by Q} + \text{Work by R} \] \[ 6x + 3(x - 1) + 2(x - 5) = 108 \] ### Step 5: Simplify the equation Expanding the equation: \[ 6x + 3x - 3 + 2x - 10 = 108 \] Combining like terms: \[ (6x + 3x + 2x) - 13 = 108 \] \[ 11x - 13 = 108 \] ### Step 6: Solve for \( x \) Adding 13 to both sides: \[ 11x = 121 \] Dividing by 11: \[ x = \frac{121}{11} = 11 \] ### Conclusion The work has been completed in **11 days**. ---

To solve the problem step by step, we will calculate the efficiency of each worker and then determine how long they worked together before Q and R left. ### Step 1: Calculate the efficiency of P, Q, and R - P can complete the work in 18 days, so his efficiency is: \[ \text{Efficiency of P} = \frac{1}{18} \text{ of the work per day} \] - Q can complete the work in 36 days, so his efficiency is: ...
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PEARSON IIT JEE FOUNDATION-TIME AND WORK, PIPES AND CISTERNS-CONCEPT APPLICATION (LEVEL-2)
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