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The circle (x-a)^2+(y-a)^2=a^2 is rolled...

The circle `(x-a)^2+(y-a)^2=a^2` is rolled on the `y-a xi s` in the positive direction through one complete revolution. Find the equation of the circle in its new-position.

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The correct Answer is:
`( x - a)^(2) + (y - (a + 2 pi a ))^(2) = a^(2)`
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