Lines 5x + 12 y -10=0 and 5x - 12y - 40=...

Lines `5x + 12 y -10=0` and `5x - 12y - 40=0`touch a circle `C_(1)` of diameter 6.If the centre of `C_(1)` lies in the first quadrant, find the equation of the circle `C_(2)` which is concentric with `C_(1)` and cuts, intercepts of length 8 on these lines.

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The correct Answer is:

`x^(2) + y^(2) - 10x - 4y + 4 = 0 ` .

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