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Find the equation of the straight line t...

Find the equation of the straight line through two points :
`(i) (0,2)` and `(0,4)` `(ii) (2,6)` and `(2,5)`

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The correct Answer is:
To find the equations of the straight lines through the given points, we will use the two-point form of the equation of a straight line. The formula is: \[ \frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1} \] where \((x_1, y_1)\) and \((x_2, y_2)\) are the two points through which the line passes. ### Part (i): Points (0, 2) and (0, 4) 1. **Identify the points**: - Let \((x_1, y_1) = (0, 2)\) - Let \((x_2, y_2) = (0, 4)\) 2. **Substitute the points into the formula**: \[ \frac{y - 2}{4 - 2} = \frac{x - 0}{0 - 0} \] 3. **Simplify the equation**: - The denominator \(0 - 0\) indicates that the line is vertical. - Since both points have the same x-coordinate (0), the equation of the line is: \[ x = 0 \] ### Part (ii): Points (2, 6) and (2, 5) 1. **Identify the points**: - Let \((x_1, y_1) = (2, 6)\) - Let \((x_2, y_2) = (2, 5)\) 2. **Substitute the points into the formula**: \[ \frac{y - 6}{5 - 6} = \frac{x - 2}{2 - 2} \] 3. **Simplify the equation**: - The denominator \(2 - 2\) indicates that the line is vertical. - Since both points have the same x-coordinate (2), the equation of the line is: \[ x = 2 \] ### Final Answers: 1. For points (0, 2) and (0, 4): **x = 0** 2. For points (2, 6) and (2, 5): **x = 2**
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Knowledge Check

  • Equation of straight line passing through the points (2,0) and (0, -3) is

    A
    `(x)/(2) - (y)/(3) =1`
    B
    `(y)/(3) - (x)/(2) =1`
    C
    `(x)/(3) - (y)/(2) = 1`
    D
    `(y)/(2) - (x)/(3) =1 `
  • Find sum of the slope of the lines passing through the following points : (i) (0,3) and (5,1) (ii) (-1,2) and (2,5)

    A
    -3/5
    B
    3/5
    C
    7/5
    D
    1
  • Find the equation of the straight line which passes through the points (5,6) and whose gradient is 2.

    A
    `y-6=2 (x-5)`
    B
    `y-5=2(x-6)`
    C
    `y-6=2 (x-6)`
    D
    `y-5=2(x-5)`
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