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find the equation of a line passing t...

find the equation of a line passing through (3,-2)and perpendicular to the line `x-3y+5=0`

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The correct Answer is:
`3x+y-7=0`
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Knowledge Check

  • Equation of a line passing through (1,-2) and perpendicular to the line 3x-5y+7=0 is

    A
    5x+3y+1=0
    B
    3x+5y+1=0
    C
    5x-3y-1=0
    D
    3x-5y+1=0

  • The equation of a line passing through (-2,-4) and perpendicular to the line 3x-y+5=0 is :

    A
    3y+x-8=0
    B
    3x+y+6=0
    C
    x+3y+14=0
    D
    none of these

  • The equation of a line passing through (-2,-4) and perpendicular to the line 3x-y+5=0 is :

    A
    3y+x-8=0
    B
    3x+y+6=0
    C
    x+3y+14=0
    D
    none of these

    • Similar Questions

    Explore conceptually related problems

    Find the equation of the line passing through (3,-5) and perpendicular to the line through the points (2,5) and (-3,6)

    Find the equation of line pair passing through (2,3) and perpendicular to the line 3x^(2)-8xy+5y^(2)

    Find the equation of the line passing through (-3, 5) and perpendicular to the line through the points (2, 5) and (-3, 6) .

    Equation of a line passing through (-1,2,-3) and perpendicular to the plane 2x+3y+z+5=0 is

    Equatioin of a line passing through (-1,2.-3) and perpendicular to the plane 2x+3y+z+5=0 is

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