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Differentiate the following w.r.t. x : ...

Differentiate the following w.r.t. x :
`(xcosx)^(x)`

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To differentiate the function \( y = (x \cos x)^x \) with respect to \( x \), we can use logarithmic differentiation. Here’s the step-by-step solution: ### Step 1: Take the logarithm of both sides We start by taking the natural logarithm of both sides: \[ \ln y = \ln((x \cos x)^x) \] ### Step 2: Simplify using logarithmic properties Using the property of logarithms that states \( \ln(a^b) = b \ln a \), we can simplify: \[ \ln y = x \ln(x \cos x) \] ### Step 3: Differentiate both sides Now, we differentiate both sides with respect to \( x \). Using the chain rule on the left side and the product rule on the right side: \[ \frac{1}{y} \frac{dy}{dx} = \frac{d}{dx}(x \ln(x \cos x)) \] ### Step 4: Apply the product rule Using the product rule on the right side: \[ \frac{d}{dx}(x \ln(x \cos x)) = \ln(x \cos x) + x \frac{d}{dx}(\ln(x \cos x)) \] ### Step 5: Differentiate \( \ln(x \cos x) \) Now, we need to differentiate \( \ln(x \cos x) \): \[ \frac{d}{dx}(\ln(x \cos x)) = \frac{1}{x \cos x} \cdot \frac{d}{dx}(x \cos x) \] Using the product rule again for \( x \cos x \): \[ \frac{d}{dx}(x \cos x) = \cos x - x \sin x \] So, \[ \frac{d}{dx}(\ln(x \cos x)) = \frac{\cos x - x \sin x}{x \cos x} \] ### Step 6: Substitute back into the equation Now we substitute this back into our differentiation equation: \[ \frac{1}{y} \frac{dy}{dx} = \ln(x \cos x) + x \cdot \frac{\cos x - x \sin x}{x \cos x} \] This simplifies to: \[ \frac{1}{y} \frac{dy}{dx} = \ln(x \cos x) + \frac{\cos x - x \sin x}{\cos x} \] ### Step 7: Multiply by \( y \) Now, multiply both sides by \( y \) to solve for \( \frac{dy}{dx} \): \[ \frac{dy}{dx} = y \left( \ln(x \cos x) + \frac{\cos x - x \sin x}{\cos x} \right) \] Substituting back \( y = (x \cos x)^x \): \[ \frac{dy}{dx} = (x \cos x)^x \left( \ln(x \cos x) + \frac{\cos x - x \sin x}{\cos x} \right) \] ### Final Answer Thus, the derivative of \( (x \cos x)^x \) with respect to \( x \) is: \[ \frac{dy}{dx} = (x \cos x)^x \left( \ln(x \cos x) + 1 - x \tan x \right) \]
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MODERN PUBLICATION-CONTINUITY AND DIFFERENTIABILITY-EXERCISE 5(i) (SHORT ANSWER TYPE QUESTIONS)
  1. Differentiate the following w.r.t. x : x^(sin^(-1)x)

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  2. Differentiate the following w.r.t. x : x^(x)sin^(-1)sqrtx

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  3. Differentiate the following w.r.t. x : (sinx)^(logx),sinxgt0

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  4. Differentiate the following w.r.t. x : (sinx)^(tanx)

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  5. Differentiate the following w.r.t. x : (sinx)^(sinx)

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  6. Differentiate the following w.r.t. x : (sec^(2)x)^(1//x)

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  7. Differentiate the following w.r.t. x : (xcosx)^(x)

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  8. Differentiate the following w.r.t. x : (x)^(logx)

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  9. Differentiate the following w.r.t. x : (logx)^(logx),xgt1

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  10. Differentiate the following w.r.t. x : x^(sin2x+cos2x)

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  11. Differentiate the following w.r.t. x : x^(sinx+cosx)

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  12. Differentiate the following w.r.t. x : (logx)^(x)

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  13. Differentiate the following w.r.t. x : (sin^(-1)x)^(x)

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  14. Differentiate the following w.r.t. x : (tan^(-1)x)^(x)

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  15. Differentiate the following w.r.t. x : x^(cos^(-1)x)

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  16. Differentiate the following w.r.t. x : (sinx)^(cos^(-1)x)

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  17. Differentiate the following w.r.t. x : (sinx-cosx)^(sinx-cosx),pi/4l...

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  18. Differentiate the following w.r.t. x : cos(x^(x))

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  19. Differentiate the following w.r.t. x : (1+x)^(logx)

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  20. Differentiate the following w.r.t. x : (logx)^(cosx)

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