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int0^1 sin^-1 x dx=pi/2-1...

`int_0^1 sin^-1 x dx=pi/2-1`

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int_0^1 sin^-1x dx=pi/2-1

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Knowledge Check

  • If I_1 = int_0^(pi//2) x/(sin x) dx and I_2 = int_0^1 (tan^(-1) x)/(x) dx , then (I_1)/(I_2) =

    A
    `1/2`
    B
    `1`
    C
    `2`
    D
    `pi/2`

  • int_(0)^(1) |sin 2pi x|dx id equal to

    A
    0
    B
    `-(1)/(pi)`
    C
    `(1)/(pi)`
    D
    `(2)/(pi)`

  • Integral int_(0)^(1) |sin 2pi x|dx is equal to

    A
    0
    B
    `-(1)/(pi)`
    C
    `(1)/(pi)`
    D
    `(2)/(pi)`

    • Similar Questions

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    int_0^pi (x sin x)/(1+sin x) dx=pi/2 (pi-2)

    (i) int_0^pi (sin^2 x/2- cos^2 x/2) dx (ii) int_0^(pi//2) (sin^2x)/(1+cosx)^2 dx

    show that (a) int_(0) ^(2pi) sin ^(3) x dx = 0 , (b) int_(-1)^(1) e^(-x^(2)) dx = 2 int_(0)^(1) e^(-x^(2)) dx

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    int_0^1d/(dx){sin^(-1)((2x)/(1+x^2))}dx is equal to 0 (b) pi (c) pi//2 (d) pi//4

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