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If the vertices A,B,C of a triangle ABC ...

If the vertices A,B,C of a triangle ABC are (1,2,3),(-1,0,0) ,(0,1,2) , respectively, then find `angleABC`.

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The correct Answer is:
`=cos^(-1)((10)/(sqrt(102)))`.
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MODERN PUBLICATION-VECTOR ALGEBRA -Ncert File Question from Ncert Book (Exercise 10.3)
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