Given two independent events A and B such that
`P(A)=0.3,P(B)=0.6`,
then P(A and not B) = 0.18.

Answer

To solve the problem, we need to find \( P(A \text{ and not } B) \) given the probabilities of two independent events \( A \) and \( B \).

### Step-by-Step Solution:

1. **Identify the given probabilities:**
- \( P(A) = 0.3 \)
- \( P(B) = 0.6 \)

2. **Understand the relationship between independent events:**
- For independent events, the probability of both events occurring is given by:
\[ P(A \cap B) = P(A) \times P(B) \]

3. **Calculate \( P(A \cap B) \):**
\[ P(A \cap B) = P(A) \times P(B) = 0.3 \times 0.6 = 0.18 \]

4. **Find \( P(A \text{ and not } B) \):**
- The probability of event \( A \) occurring while event \( B \) does not occur can be calculated using:
\[ P(A \text{ and not } B) = P(A) - P(A \cap B) \]
- Substitute the known values:
\[ P(A \text{ and not } B) = P(A) - P(A \cap B) = 0.3 - 0.18 = 0.12 \]

5. **Conclusion:**
- The calculated value of \( P(A \text{ and not } B) \) is \( 0.12 \).
- The statement in the question claims that \( P(A \text{ and not } B) = 0.18 \), which is incorrect.

### Final Answer:
The statement is **false**.

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