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One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals

A

`(1)/(7)`

B

`(5)/(14)`

C

`(1)/(50)`

D

`(1)/(14)`

Text Solution

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The correct Answer is:
D
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