Consider the reaction
`Cr_(2)O_(7)^(2-)+14H^(+)6e^(-)rarr2Cr^(3+)+8H_(2)O`
What is the quantity of electricity in coulombs needed to reduce 1 mole of `Cr_(2)O_(7)^(2)`?

Explanation

6 mol of electrons are required to reduce 1 mole of `Cr_(2)O_(7)^(2-)`
Now 1 mol of eletrons =96500C.
6 mol of electrons `=96500xx6=5.79xx10^(5)C`.