Silver crystallises in a fcc lattice. The edge length of its unit is `4.077xx10^(-8)cm` and its density is `10.5g cm^(-3)`. Claculate on this basis of the atomic mass of silver `(N_(A)=6.02xx10^(23) "mol"^(-1))`

Explanation

Here, `a=4.077xx10^(-8)cm ,d=10.5g cm^(-3)`
`N_(A)=6.02xx10^(23)"mol"^(-1)`
for fcc lattice, `x=4d=(z.M)/(9^(3).N_(A))`
`:. M=(d xxa^(3)xxN_(A))/(z)=(10.5xx(4.077xx10^(-8))^(3))/(4)=107.09 g "mol"^(-1)`