Home
Class 12
CHEMISTRY
1.60 g of a metal A and 0.96 g of a met...

1.60 g of a metal A and 0.96 g of a metal B when treated with excess of dilute acid, separately, produced the same amount of hydrogen. Calculate the equivalent weight of A if the equivalent weight of B is 12.

Text Solution

Verified by Experts

The correct Answer is:
20
Promotional Banner

Topper's Solved these Questions

  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE|Exercise Exercise -1 (Part-II)|19 Videos
  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE|Exercise Exercise -1 (Part-III)|1 Videos
  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE|Exercise Miscellaneous solved problems|12 Videos
  • ELECTROCHEMISRY

    RESONANCE|Exercise Advanced Level Problems|88 Videos
  • FUNDAMENTAL CONCEPT

    RESONANCE|Exercise ORGANIC CHEMISTRY(Fundamental Concept )|40 Videos

Similar Questions

Explore conceptually related problems

The equivalent weight of a metal is 12. What is the equivalent weight of its oxide?

3.0 g of metal chloride gave 2.0 g of metal. Calculate the equivalent weight of the metal.

1.0 g of a metal oxide gave 0.2 g of metal. Calculate the equivalent weight of the metal.

Calculate the equivalent weight of metal, if the oxide of a metal contains 32% oxygen.

0.32 g of metal gave on treatment with an acid 112 mL of hydrogen at NTP. Calculate the equivalent weight of the metal

RESONANCE-EQUIVALENT CONCEPT & TITRATIONS-Exercise -1 (Part-I )
  1. Determine the equivalent weight of the following ions : (a) Na^(+) "...

    Text Solution

    |

  2. Determine the equivalent weights of the following salts: (a) NaCl" "...

    Text Solution

    |

  3. 1.12 litre dry chlorine gas at STP was passed over a heated metal when...

    Text Solution

    |

  4. A mixture of CuS (molecular weight = M(1)) and Cu(2)S (molecular weigh...

    Text Solution

    |

  5. Determine the equivalent weight of the following oxidising and reducin...

    Text Solution

    |

  6. 0.98 g of the metal sulphate was dissolved in water and excess of bari...

    Text Solution

    |

  7. A dilute solution of H(2)SO(4) is made by adding 5 mL of 3N H(2)SO(4) ...

    Text Solution

    |

  8. What volume at NTP of gaseous ammonia will be required to be passed in...

    Text Solution

    |

  9. 1.60 g of a metal A and 0.96 g of a metal B when treated with excess ...

    Text Solution

    |

  10. It requires 40mL of 1 M Ce^(4+) to titrate 20mL of 1 M Sn^(2+) " to "S...

    Text Solution

    |

  11. 25 mL of a solution of Fe^(2+) ions was titrated with a solution of th...

    Text Solution

    |

  12. How many mL of 0.3M K(2)Cr(2)O(7) (acidic) is required for complete ox...

    Text Solution

    |

  13. 10g sample of bleaching powder was dissolved into water to make the so...

    Text Solution

    |

  14. A mixture containing As(2)O(3) and As(2)O(5) required 20 mL of 0.05 N ...

    Text Solution

    |

  15. 20ml ofH(2)O(2) after acidification with dilute H2SO(4)required 30mlof...

    Text Solution

    |

  16. A 100 mL sample of water was treated to convert any iron present to Fe...

    Text Solution

    |

  17. By which reason temporary and permanent hardness occur ?

    Text Solution

    |

  18. Define two method by which we can soften the water sample.

    Text Solution

    |