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There is one tightly wound long solenoid...

There is one tightly wound long solenoid carrying current 2 A. Solenoid have 100 turns per cm. `H_1` is the magnetic intensity and `B_1` is the magnetic field at the centre of solenoid. Now an iron core is inserted inside the solenoid. Intensity of magnetization in the core is `4 xx 10^6` A/m. New values of magnetic intensity and magnetic field at the centre becomes `H_2` and `B_2`
Value of `H_2//H_1 ` is

A

infinity

B

`4 xx 10^6`

C

`2 xx 10^3`

D

1

Text Solution

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The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the Magnetic Intensity (H1) of the Solenoid The magnetic intensity \( H_1 \) in a solenoid is given by the formula: \[ H_1 = n \cdot I \] Where: - \( n \) is the number of turns per meter - \( I \) is the current in amperes Given: - The solenoid has 100 turns per cm, which can be converted to turns per meter: \[ n = 100 \, \text{turns/cm} = 100 \times 100 = 10,000 \, \text{turns/m} \] - The current \( I = 2 \, \text{A} \) Now substituting the values: \[ H_1 = 10,000 \, \text{turns/m} \times 2 \, \text{A} = 20,000 \, \text{A/m} = 2 \times 10^4 \, \text{A/m} \] ### Step 2: Calculate the Magnetic Field (B1) at the Center of the Solenoid The magnetic field \( B_1 \) at the center of the solenoid is given by: \[ B_1 = \mu_0 H_1 \] Where \( \mu_0 \) (the permeability of free space) is: \[ \mu_0 = 4\pi \times 10^{-7} \, \text{T m/A} \] Substituting the value of \( H_1 \): \[ B_1 = 4\pi \times 10^{-7} \, \text{T m/A} \times 2 \times 10^4 \, \text{A/m} \] Calculating this: \[ B_1 = 8\pi \times 10^{-3} \, \text{T} \] ### Step 3: Determine the New Magnetic Intensity (H2) After Inserting the Iron Core When an iron core is inserted into the solenoid, the magnetic intensity \( H \) remains unchanged. Therefore: \[ H_2 = H_1 = 2 \times 10^4 \, \text{A/m} \] ### Step 4: Calculate the Ratio \( \frac{H_2}{H_1} \) Since \( H_2 \) remains the same as \( H_1 \): \[ \frac{H_2}{H_1} = \frac{H_1}{H_1} = 1 \] ### Final Answer Thus, the value of \( \frac{H_2}{H_1} \) is: \[ \boxed{1} \] ---

To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the Magnetic Intensity (H1) of the Solenoid The magnetic intensity \( H_1 \) in a solenoid is given by the formula: \[ H_1 = n \cdot I \] Where: ...
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