An alternating voltage given by `V = 140 sin 314 t` is connected across a pure resistor of 50 ohm. Find (i) the frequency of the source. (ii) the rms current thought the resistor.

Explanation

(i) Compare equations v = 140 sin 314 t with V = `V_(0)` sin `omega`t
We get `omega = 314 , 2 pi f = 314 `
` f = (314)/(2 xx 3.14) = 50 `Hz
(ii) `I_(rms) = (V_(rms))/(R) = (V_(0))/(sqrt(2 R)) = (140)/( 1.414 xx 50) = 1.98 ` A