The currents flowing in the two coils of self - inductance `L_(1)= 20 ` m H and `L_(2) = 15 ` mH are increasing at the same rate. If the the power supplied to the two coils is equal find the ratio of (i) induced voltages (ii) the currents and (iii) the energies stored in the two coils at a given instant.

Explanation

To solve the problem, we will find the ratios of induced voltages, currents, and energies stored in two coils with given self-inductances. Let's break it down step by step.

### Given Data:
- Self-inductance of coil 1, \( L_1 = 20 \, \text{mH} = 20 \times 10^{-3} \, \text{H} \)
- Self-inductance of coil 2, \( L_2 = 15 \, \text{mH} = 15 \times 10^{-3} \, \text{H} \)
- The currents in both coils are increasing at the same rate, i.e., \( \frac{di_1}{dt} = \frac{di_2}{dt} \).
- The power supplied to both coils is equal.

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