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A resistance R draws power P when connec...

A resistance `R` draws power `P` when connected to an `AC` source. If an inductance is now placed in series with the resistance, such that the impedence of the circuit becomes `Z`, the power drawn will be

A

`P sqrt((R)/(Z))`

B

`P ((R)/(Z))`

C

P

D

P`((R)/(Z))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
(d ) : When only resistance is connected then `P=V_("rms")^(2)//R`
when inductor is also there then ` P= V_("rms") I_("rms") cos delta `
`= V _("rms") (V_("rms"))/(Z) ( R)/(Z)`
`= P ((R )/(Z)^(2))`
Hence option (d ) is correct .
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