The kinetic energy of an electron is `5 eV`. Calculate the de - Broglie wavelength associated with it `( h = 6.6 xx 10^(-34) Js , m_(e) = 9.1 xx 10^(-31) kg)`

An electron in a hydrogen like atom is in an excited state3 . It has a total energy of -3 4 eV. Calculate : (a) The kinetic energy of electron . (b) The de-Broglie wavelength of electron . ( h = 6.6 xx 10^(023) , m_e = 9 .108 xx 10^(-31) kg)

Photon having energy equivalent to the binding energy of 4th state of He^(+) ion is used to eject an electron from the metal with KE/2eV . If electron is further accelerated through a potential difference of 4V then the minimum value of de Broglie wavelength associated with the electron is : (h = 6.6 xx 10^(-34) J-s , m_(e) = 9.1 xx 10^(-31) kg . 1 eV = 1.6 xx 10^(-19) J )

The kinetic energy of an electron is 4.55 xx 10^(-25)J . Calculate the wavelength . [h = 6.6 xx 10^(-34)Js , mass of electron = 9.1 xx 10^(-31)kg]

A proton (mass = 1.66 xx 10^(-27)kg) is moving with kinetic energy 5 xx 10^(-27) J calculate the de Broglie wavelength associated with it ? (h = 6.6 xx 10^(-34)Js)

An electron is accelerated under a potential difference of 64 V, the de-Brogile wavelength associated with electron is [e = -1.6 xx 10^(-19) C, m_(e) = 9.1 xx 10^(-31)kg, h = 6.623 xx 10^(-34) Js]

Find the de-Broglie wavelength associated with an electron moving with a velocity 0.5 c and rest mass = 9.1 xx 10^(-31) kg .

An electron is moving with a kinetic energy of 2.275 xx 10^(25) J . Calculate its de-Broglie wavelength. (Mass of electron = 9.1 xx 10^(-31) kg, h = 6.6 xx 10^(-34) J s)

Calculate the energy of an electron having de-Broglie wavelength 5500Å. Given, h=6.62xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg .

Calculate the wavelength associated with an electron (mass = 9.1 xx 10^(-31)kg) having kinetic energy 2.275 xx 10^(-25) J .

What amount of energy (in eV) should be added to an electron to reduce its de-Broglie its de-Broglie wavelength from 100 to 50 pm? Given h=6.62xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg .