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In Rutherford alpha-sattering experiment...

In Rutherford `alpha`-sattering experiment , the ratio of number of particles scattered at an angle of `180^@` to the number of particles scattered at an angle of `90^@` is `alpha:4`. What is the value of `alpha` ?

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To solve the problem, we need to find the value of α given the ratio of the number of particles scattered at angles of 180° and 90° in Rutherford's alpha scattering experiment. Let's break it down step by step. ### Step 1: Understand the Given Information We know that the ratio of the number of particles scattered at an angle of 180° to those scattered at an angle of 90° is given as α:4. This can be expressed mathematically as: \[ \frac{N(180^\circ)}{N(90^\circ)} = \frac{\alpha}{4} \] ### Step 2: Use the Scattering Formula In Rutherford's alpha scattering experiment, the number of particles scattered at an angle θ is inversely proportional to \( \sin^4(\theta/2) \). Therefore, we can write: \[ N(\theta) \propto \frac{1}{\sin^4(\theta/2)} \] This means: \[ N(180^\circ) \propto \frac{1}{\sin^4(90^\circ)} \quad \text{and} \quad N(90^\circ) \propto \frac{1}{\sin^4(45^\circ)} \] ### Step 3: Calculate the Values of Sine Now we need to calculate the sine values: - \( \sin(90^\circ) = 1 \) - \( \sin(45^\circ) = \frac{1}{\sqrt{2}} \) ### Step 4: Substitute the Sine Values into the Formula Substituting these values into our expressions for \( N(180^\circ) \) and \( N(90^\circ) \): \[ N(180^\circ) \propto \frac{1}{1^4} = 1 \] \[ N(90^\circ) \propto \frac{1}{\left(\frac{1}{\sqrt{2}}\right)^4} = \frac{1}{\frac{1}{4}} = 4 \] ### Step 5: Set Up the Ratio Now we can set up the ratio: \[ \frac{N(180^\circ)}{N(90^\circ)} = \frac{1}{4} \] ### Step 6: Relate to the Given Ratio From the problem statement, we have: \[ \frac{N(180^\circ)}{N(90^\circ)} = \frac{\alpha}{4} \] Setting the two expressions for the ratio equal to each other gives: \[ \frac{1}{4} = \frac{\alpha}{4} \] ### Step 7: Solve for α To find α, we can multiply both sides by 4: \[ 1 = \alpha \] Thus, the value of α is: \[ \alpha = 1 \] ### Final Answer The value of α is **1**. ---

To solve the problem, we need to find the value of α given the ratio of the number of particles scattered at angles of 180° and 90° in Rutherford's alpha scattering experiment. Let's break it down step by step. ### Step 1: Understand the Given Information We know that the ratio of the number of particles scattered at an angle of 180° to those scattered at an angle of 90° is given as α:4. This can be expressed mathematically as: \[ \frac{N(180^\circ)}{N(90^\circ)} = \frac{\alpha}{4} \] ...
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