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The electron is moving with a velocity c...

The electron is moving with a velocity `c/3`. The de-Broglie wavelength of electron is observed to be equal to a moving photon. The ratio of kinetic energy of electron to that energy of photon is found to be a:6. Find the value of a.

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To solve the problem, we need to find the value of \( a \) given that the ratio of the kinetic energy of the electron to the energy of the photon is \( \frac{a}{6} \). ### Step-by-step Solution: 1. **Identify the velocity of the electron**: The electron is moving with a velocity \( v = \frac{c}{3} \). 2. **Calculate the de-Broglie wavelength of the electron**: The de-Broglie wavelength \( \lambda_e \) of the electron is given by the formula: \[ \lambda_e = \frac{h}{mv} \] where \( m \) is the mass of the electron and \( v \) is its velocity. Substituting \( v = \frac{c}{3} \): \[ \lambda_e = \frac{h}{m \cdot \frac{c}{3}} = \frac{3h}{mc} \] 3. **Determine the wavelength of the photon**: According to the problem, the de-Broglie wavelength of the electron is equal to the wavelength of the moving photon, \( \lambda_p \). Therefore: \[ \lambda_p = \lambda_e = \frac{3h}{mc} \] 4. **Calculate the energy of the photon**: The energy \( E \) of a photon is given by: \[ E = \frac{hc}{\lambda_p} \] Substituting \( \lambda_p = \frac{3h}{mc} \): \[ E = \frac{hc}{\frac{3h}{mc}} = \frac{mc^2}{3} \] 5. **Calculate the kinetic energy of the electron**: The kinetic energy \( KE \) of the electron is given by: \[ KE = \frac{1}{2} mv^2 \] Substituting \( v = \frac{c}{3} \): \[ KE = \frac{1}{2} m \left(\frac{c}{3}\right)^2 = \frac{1}{2} m \cdot \frac{c^2}{9} = \frac{mc^2}{18} \] 6. **Find the ratio of kinetic energy of the electron to the energy of the photon**: We need to find the ratio \( \frac{KE}{E} \): \[ \frac{KE}{E} = \frac{\frac{mc^2}{18}}{\frac{mc^2}{3}} = \frac{1/18}{1/3} = \frac{3}{18} = \frac{1}{6} \] 7. **Relate the ratio to \( a \)**: According to the problem, this ratio is given as \( \frac{a}{6} \): \[ \frac{1}{6} = \frac{a}{6} \] Therefore, we can conclude that: \[ a = 1 \] ### Final Answer: The value of \( a \) is \( 1 \).

To solve the problem, we need to find the value of \( a \) given that the ratio of the kinetic energy of the electron to the energy of the photon is \( \frac{a}{6} \). ### Step-by-step Solution: 1. **Identify the velocity of the electron**: The electron is moving with a velocity \( v = \frac{c}{3} \). 2. **Calculate the de-Broglie wavelength of the electron**: ...
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