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A hydrogen atom in its ground state is i...

A hydrogen atom in its ground state is irradiated by light of wavelength `970Å` Taking `hc//e = 1.237 xx 10^(-6)`eV m and the ground state energy of hydrogen atom as ` - 13.6 eV` the number of lines present in the emmission spectrum is

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The correct Answer is:
6
Photon energy `=(hc)/lambda=(1.237xx10^(-6))/(970xx10^(-10))` =12.75 eV
Absorption of this photon changes the energy to =-13.6+12.75=-0.85 eV
Hence atom is excited to fourth quantum state. Number of possible transitions from the `4^(th)` quantum state `=.^4C_2`=6
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