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An electron ina hydrogen atom undergoes ...

An electron ina hydrogen atom undergoes a transition from an orbit with quantum number `n_(i) ` to another with quantum number `n_(f)` . `V_(i)` and `V_(f)` are respectively the initial and final potential energies of the electron. If `( V_(i))/( V_(f)) = 6.25`, then the smallest possible `n_(f ) ` is

Text Solution

Verified by Experts

The correct Answer is:
5

PE =`-27.2/n^2`
`V_f/V_i=(-27.2/n_f^2)/(-27.2/n_i^2)=1/6.25`
`6.25=n_f^2/n_i^2`
`n_f/n_i=2.5=5/2`
Hence smallest value of `n_f`=5.
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