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In a triode value for a grid voltage Vg=...

In a triode value for a grid voltage `V_g=-1.2V` , the phase current `I_p` and plate voltage `V_p` are given `I_p=(-5+0.1 V_0),I_p` in `mA and V_p` in volt . When grid voltage is changed to - 3.2 V at constant plate voltage of 150 V , a plate current of 5 mA is observed , then
Plate resistance `R_p` is

A

`10^2 Omega`

B

`10^3 Omega`

C

`10^4 Omega`

D

`10^5 Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`V_g=-1.2 V "Now " i_p=(-50+0.1V_p)10^(-3)A " "...(i)`
then `((Deltai_p)/(Deltai_p))=0.1xx10^(-3)AV^(-1)`
then plate resistance
`((Deltai_p)/(Deltai_p))=1/ (0.1xx10^(-3))=10^(4)Omega`
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Knowledge Check

  • In a triode value for a grid voltage V_g=-1.2V , the phase current I_p and plate voltage V_p are given I_p=(-5+0.1 V_0),I_p in mA and V_p in volt . When grid voltage is changed to - 3.2 V at constant plate voltage of 150 V , a plate current of 5 mA is observed , then Amplification factor mu is

    A
    25
    B
    5.5
    C
    10.5
    D
    16.67

  • In a triode value for a grid voltage V_g=-1.2V , the phase current I_p and plate voltage V_p are given I_p=(-5+0.1 V_0),I_p in mA and V_p in volt . When grid voltage is changed to - 3.2 V at constant plate voltage of 150 V , a plate current of 5 mA is observed , then Tran conductance inductance g_m is

    A
    `1.5 xx10^3 ohm^(-1)`
    B
    `2.5 xx10^3 ohm^(-1)`
    C
    `3.0 xx10^3 ohm^(-1)`
    D
    `3.5 xx10^3 ohm^(-1)`

  • In a triode value for a grid voltage V_g=-1.2V , the phase current I_p and plate voltage V_p are given I_p=(-5+0.1 V_0),I_p in mA and V_p in volt . When grid voltage is changed to - 3.2 V at constant plate voltage of 150 V , a plate current of 5 mA is observed , then Voltage amplification for 20 kOmega load in plate circuit is

    A
    5.5
    B
    10.5
    C
    16.67
    D
    20.2

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