Home
Class 12
PHYSICS
The current voltage relation of diode is...

The current voltage relation of diode is given by `I=(e^(1000V//T)-1)` mA , where the applied voltage V is in volts and the temperature T is in degree Kelvin . If a student makes an error measuring `pm0.01` V while measuring the current of 5 mA at 300K, what will be the error in the error in the value of current in mA ?

A

0.5 mA

B

0.05 mA

C

0.2 mA

D

0.02 mA

Text Solution

Verified by Experts

The correct Answer is:
C
`5 = e^(100 (V)/(T))-1`
`impliese^(1000V/T=6)" "....(1)`
Again , `I=e^(1000V/T)-1`
`(dI)/(dV)=e^((1000V)/T)1000/T`
`dI=1000/Te^(1000/TV)dV`
Using (1) , `DeltaI=100/Txx6xx0.01`
`=60/T=60/(300)=0.2mA`
So correct choice is (c) .
Promotional Banner

Topper's Solved these Questions

  • SOLIDS & SEMICONDUCTOR DEVICES

    MODERN PUBLICATION|Exercise Recent Competitive Questions|26 Videos

  • SOLIDS & SEMICONDUCTOR DEVICES

    MODERN PUBLICATION|Exercise Revision Test|28 Videos

  • SOLIDS & SEMICONDUCTOR DEVICES

    MODERN PUBLICATION|Exercise Multiple Choice Questions - LEVEL -II|58 Videos

  • ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise RCQ|8 Videos

  • TRANSFERENCE OF HEAT

    MODERN PUBLICATION|Exercise Recent Competitive Questions|4 Videos

Similar Questions

Explore conceptually related problems

Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are 3% each, then error in the value of resistance of the wire is :

The heat generated in a circuit is given by Q=I^(2)Rt, where I is current, R is resistance and t is time. If the percentage errors in measuring I,R and t are 2%,1% and 1% respectively, then the maximum error in measuring heat will be :

In the determination of resistance R is calculated from R =V//I where V is the reading of the voltmeter and I is the reading of the ammeter. The values obtained are V = 10 pm 0.2 V and I = 0.5 pm 0.01 A. The maximum percentage error in the measurement of resistance is

The resistance of a metal is given by R=(V)/(I), where V is potential difference and I is the current. In a circuit the potential difference across resistance is V=(8+-0*5) V and current in resistance, I=(4+-0*2)A . And current in resistance with its percentage error :

In a reverse biased diode when the applied voltage changes by 1 V, the current is found to change by 0.5 muA . The reverse bias resistance of the diode is