At a certain temperature, the value of equilibrium constant for the reaction:
`A_2+2B_2(g) hArr 2AB_2` is 100.
What is the equilibrium constant for the reaction.
`AB_2(g) hArr 1/2A_2 + B_2` ?

Explanation

To find the equilibrium constant for the reaction \( AB_2(g) \rightleftharpoons \frac{1}{2} A_2 + B_2 \), we start with the given equilibrium constant for the reaction:

\[ A_2 + 2B_2 \rightleftharpoons 2AB_2 \]

The equilibrium constant \( K \) for this reaction is given as 100.

### Step 1: Write the expression for the equilibrium constant
The equilibrium constant \( K \) for the reaction \( A_2 + 2B_2 \rightleftharpoons 2AB_2 \) can be expressed as:
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