The solubility product of `Mg(OH)_2` is `1.2 xx 10^(-11)`. Calculate its solubility in 0.1 M NaOH solution.

Explanation

To calculate the solubility of `Mg(OH)₂` in a 0.1 M NaOH solution, we can follow these steps:

### Step 1: Write the dissociation equation for `Mg(OH)₂`
`Mg(OH)₂` is a sparingly soluble salt that dissociates in water as follows:
\[ \text{Mg(OH)}_2 (s) \rightleftharpoons \text{Mg}^{2+} (aq) + 2 \text{OH}^- (aq) \]

### Step 2: Define the solubility
Let the solubility of `Mg(OH)₂` in the solution be \( S \). Therefore, at equilibrium:
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