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the value of equilibrium constant for th...

the value of equilibrium constant for the reaction
`HI(g) hArr 1//2 H_(2) (g) +1//2 I_(2) (g) " is " 8.0`
The equilibrium constant for the reaction
`H_(2) (g) +I_(2) (g) hArr 2HI(g)` will be

A

`1//16`

B

`1//64`

C

`16`

D

`1//8`

Text Solution

Verified by Experts

The correct Answer is:
B
`HI hArr 1/2H_2 +1/2I_2 " " K_1`=8.0
`2HI hArr H_2+I_2 " " K_2` =64.0
`H_2+I_2 hArr 2HI " " K_3=1/64`
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