Equal volumes of three acid solutions of `pH 3, 4` and `5` are mixed in a vessel. What will be the `H^(+)` ion concentration in the mixture?

Options

A. `1.11xx10^(-4)` M
B. `3.7xx10^(-4)` M
C. `3.7xx10^(-3)` M
D. `1.11xx10^(-3)` M

Answer

B

Explanation

`N_1V_1+N_2V_2+N_3V_3 =N_4V_4`
Let the volume of each acid solution mixed be 1 L
`10^(-3)xx1+10^(-4) xx1 + 10^(-5)xx1=N_4xx3`
`10^(-3) +10^(-4) + 10^(-5) =N_4xx3`
`N_4 xx3 =1.11xx10^(-3)`
`N_4=(1.11xx10^(-3))/3 =0.37xx10^(-3)`
`[H^+]=3.7xx10^(-4)` M