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In a buffer solution containing equal co...

In a buffer solution containing equal concentration of `B^(-)` and `HB`, the `K_(b)` for `B^(-)` is `10^(-10)`. The `pH` of buffer solution is

A

6

B

4

C

10

D

7

Text Solution

Verified by Experts

The correct Answer is:
B
pOH=`pK_b+log ([B^-])/"[HB]"`
` pK_b=-log K_b=-(log 10^(-10))=10`
`therefore` pOH=10 (`because` concentration of `[B^-]=[HB]`)
`therefore ` pH=14-10=4
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