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For the reaction C(s) +CO(2)(g) rarr 2CO...

For the reaction `C(s) +CO_(2)(g) rarr 2CO(g), k_(p)=63` atm at 100 K. If at equilibrium `p_(CO)=10p_(CO_(2)) ` then the total pressure of the gases at equilibrium is

A

6.3 atm

B

6.93atm

C

0.63atm

D

0.693 atm

Text Solution

Verified by Experts

The correct Answer is:
B
`K_p=(p_(CO))^2/(p_(CO_2))` or `63=((10 p_(CO_2))^2)/p_(CO_2)`
`therefore 63=100 p_(CO_2)` or `p_(CO_2)` =0.63
`p_(CO)=10xx0.63` =6.3
`p_"Total"=p_(CO_2)+p_(CO)`
=0.63+6.3=6.93 atm
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