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Solubility product of silver bromide is ...

Solubility product of silver bromide is `5.0xx10^(-13)`. The quantity of potassium bromide (molar mass taken as `120g mol^(-1)`) to be added to `1 L` of `0.05 M` solution of silver nitrate to start the precipitation of `AgBr` is

A

`6.2xx10^(-5)` g

B

`5.0xx10^(-8)` g

C

`1.2xx10^(-10)` g

D

`1.2xx10^(-9)` g

Text Solution

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The correct Answer is:
D
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