Home
Class 11
CHEMISTRY
The pH of 0.02MNH(4)Cl solution will be...

The pH of `0.02MNH_(4)Cl` solution will be : [Given `K_(b) (NH_(4)OH) = 10^(-5) and log 2 = 0.301`]

A

4.65

B

5.35

C

4.35

D

2.65

Text Solution

Verified by Experts

The correct Answer is:
B
For a salt of strong acid and weak base,
`[H^+]=sqrt((K_wxxC)/K_b)`
`[H^+]=sqrt((10^(-14)xx2xx10^(-2))/10^(-5)) `
`=sqrt(20xx10^(-12))`
`=sqrt20xx10^(-6)`
`=6-1/2 log 20`
=6-0.65
=5.35
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Objective C.(MCQs)|11 Videos

  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Objective D.(MCQs) Passage|10 Videos

  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Objective A.(MCQs)|41 Videos

  • ENVIRONMENTAL POLLUTION

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|15 Videos

  • HALOALKANES AND HALOARENES

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|12 Videos

Similar Questions

Explore conceptually related problems

P^(H) of 0.02 M NH_(4)Cl solution is

Calculate the pH of 0.01 M NH_4Cl solution at 25^@C . K_b for NH_4OH=1.81xx10^(-5)

The PH of 10^(-2)MNH_(4)CN solution would be- (Given that K_(a) of HCN=5times10^(-10) and K_(b) of ( ) agNH_(3) ) =2times10^(-5) )

Calculate the degree of hydrolysis and pH of 0.2M solution of NH_(4)C1 Given K_(b) for NH_(4)OH is 1.8 xx 10^(-5) .

What is pH of 0.02 M solution of ammonium chloride at 25^(@) C ? K_(b) (NH_(3)) = 1.8 xx 10^(-5) .

Calculate the number of moles of NH_(4)Cl that should be added to one litre of "1.0 M "NH_(4)OH to prepare buffer solution with pH=9[K_(b)=2xx10^(-5)," take log"2=0.3]

The pH of 0.02 M NH_(4)Cl (aq) (pK_(b)=4.73) is equal to

How many millimoles of MgCI_(2) should be added to just precipitate Mg(OH) in 500 ml buffer solution containing 0.1 M NH_(4)OH and 0.1M(NH_(4))_(2)SO_(4) ? {Given : K_(b) (NH_(4)OH) = 10^(-5), K_(sp) [Mg(OH)_(2)] = 10^(-11)}

MODERN PUBLICATION-EQUILIBRIUM-Objective B.(MCQs)
  1. The values of K(p)//K(c) for the following reactions at 300 K are, res...

    Text Solution

    |

  2. 20 mL of 0.1 M H2SO4 solution is added to 30 mL of 0.2 M NH4OH solutio...

    Text Solution

    |

  3. 5.1 g NH(4)SH is introduced in 3.0 L evacuated flask at 327^(@)C, 30%...

    Text Solution

    |

  4. For the equilibrium, 2H(2)O hArr H(3)O^(+) + OH^(-),the value of De...

    Text Solution

    |

  5. For the following reactions , equilibrium constants are given : S(s)...

    Text Solution

    |

  6. The molar solubility of Cd(OH)(2) is 1.84xx10^(-5)M in water. The exp...

    Text Solution

    |

  7. Consider the following reversible chemical reactions : A(2)(g)+B(2)...

    Text Solution

    |

  8. Consider the following statements (A)The pH of a mixture containing ...

    Text Solution

    |

  9. Two solids dissociates as follows A(s) rarr B(g) + C(g), K(P(1)) = x a...

    Text Solution

    |

  10. If solubility product of Zr(3)(PO(4))(4) is denotes by K(sp) and its m...

    Text Solution

    |

  11. The pH of 0.02MNH(4)Cl solution will be : [Given K(b) (NH(4)OH) = 10^...

    Text Solution

    |

  12. For the reaction 2SO(2)(g)+O(2)(g)=2SO(3)(g) deltaH=-57.2kJmol^(-1...

    Text Solution

    |

  13. In which one of the following equilibria, Kp ne Kc ?

    Text Solution

    |

  14. The molar solubility of Al(OH)(3) in 0.2 M NaOH solution is x xx 10^(...

    Text Solution

    |

  15. A weak acid HX has the dissociation constant 1 xx 10^(-5)M. It forms a...

    Text Solution

    |

  16. 0.1 mole of CH(3)CH (K(b) = 5 xx 10^(-4)) is mixed with 0.08 mole of H...

    Text Solution

    |

  17. If Ag^(+)+NH(3)hArr[Ag(NH(3))]^(+), K(1)=3.5xx10^(-3) and [Ag(NH(3))]^...

    Text Solution

    |

  18. When 2.5 mL of 2//5M weak monoacidic base (K(b) = 1 xx 10^(-12) at 25^...

    Text Solution

    |

  19. Solubility product constant (K(sp)) of salts of types MX, MX2 and M3X ...

    Text Solution

    |

  20. How many litres of water must be added to 1 L of an aqueous solution o...

    Text Solution

    |