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If Ag^(+)+NH(3)hArr[Ag(NH(3))]^(+), K(1)...

If `Ag^(+)+NH_(3)hArr[Ag(NH_(3))]^(+)`, `K_(1)=3.5xx10^(-3)` and `[Ag(NH_(3))]^(+)+NH_(3)hArr[Ag(NH_(3))_(2)]^(+)`, `K_(2)=1.74xx10^(-3)`. The formation constant of `[Ag(NH_(3))_(2)]^(+)` is :

A

`1.08xx10^7`

B

`1.08xx10^3`

C

`6.8xx10^6`

D

`6.8xx10^7`

Text Solution

Verified by Experts

The correct Answer is:
A
`K=K_fxxK._f=6.8xx10^3xx1.6xx10^3=1.08xx10^7`
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Ag^(+)+NHP(3)hArr[Ag(NH_(3))]^(+), K_(1)=3.5=10^(-3) [Ag(NH)_(3)]^(+)+NH_(3)hArr[Ag(NH_(3))_(2)]^(+),K_(2)=1.7xx10^(-3) then the formation constant of [Ag(NH_(3))_(2)]^(+) is

Ag^(+)+hArr|Ag(NH_(3))_(2)|^(+), k_(1) = 6.8 xx 10^(-3) [Ag(NH_(3))]^(+) + NH_(3)hArr |Ag(NH_(3))_(2)|, k_(2) = 1.6xx10^(-3) Then the formation constant or |Ag(NH_(3))_(2)|^(+) is

Ag^(+) + NH_(3) ltimplies [Ag(NH_(3))]^(+), k_(1)=6.8 xx 10^(-5) [Ag(NH_(3))]^(+) + NH_(3) ltimplies [Ag(NH_(3))_(2)]^(+) , k_(2) = 1.6xx10^(-3) The formation constant of [Ag(NH_(3))_(2)]^(+) is :

{:(Ag^+ +NH_3 hArr[Ag(NH_3)]^+,,K_1=3.5xx10^-3),([Ag(NH_3)]^+ +NH_3 hArr[Ag(NH_3)_2]^+,,K_2=1.8xx10^-3):} then, the overall formation constant of [Ag(NH_3)_2]^+ is :

Zn^(+2) + 2NH_(3) hArr [Zn(NH_(3))_(2)]^(+2), K_(1) = 2xx10^(-3) [Zn(NH_(3))_(2)]^(+2) + 2NH_(3) hArr [Zn(NH_(3))_(4)]^(2+), K_(2) = 1.5xx10^(-3) Find out the instability constant?

The hybridisation of Ag in [Ag(NH_3)_2]^+ complex is -

MODERN PUBLICATION-EQUILIBRIUM-Objective B.(MCQs)
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