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0.30g of an organic compound containing ...

`0.30g` of an organic compound containing `C`, `H` and Oxygen on combustion yields `0.44g CO_(2)` and `0.18g H_(2)O`. If one mole of compound weighs `60`, then molecular formula of the compound is

A

`C_(4)H_(6)O`

B

`CH_(2)O`

C

`C_(2)H_(4)O_(2)`

D

`C_(3)H_(8)O`

Text Solution

Verified by Experts

The correct Answer is:
C
Percentage of C`=(12)/(44)xx(0.44)/(0.30)xx100=40%`
Percentage of H`=(2)/(18)xx(0.18)/(0.30)xx100=6.67%`
Percentage of O `=100-(40+6.67)=53.33%`
Calculation of empirical formula

Empirical formula `=CH_(2)O`
Empirical formula mass `=12+2xx1+16=30`
Molecular mass `=60`
`n=(60)/(30)=2`
`:.` Molecular formula `=(CH_(2)O)_(2)=C_(2)H_(4)O_(2)`
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